analysis of two transistors ib,ic,ie? - Electrical Engineering Stack Exchange

is ib current correct went kvl through first transistor

your forgetting re.

you need use effective resistances r4 , r6, value

\$r4_e = r4 * (1+\beta) = 40,000 * 101 = 4,040,000\omega\$ \$r6_e = r6 * (1+\beta) = 1,000 * 101 = 101,000\omega\$

using base circuit looks this.

^{simulate circuit – schematic created using circuitlab}

you solve using various methods, shortcut realise that, ideal vbe, voltage @ top of both emitter resistors identical. such can treat both legs being in parallel. circuit can further simplified to..

^{simulate circuit}

now should able calculate current through circuit as..

\$i_{rb} = (2.6 - 0.6)/(2,260 + 98,540) = 19.84ua\$

that makes base voltages both..

\$v_b = 2.6 - 19.84ua * 2.26k\omega = 2.555v\$

so

\$ib1 = (2.555-0.6)/4.04m\omega = 0.484ua\$.. , \$ib2 = (2.555-0.6)/101k\omega = 19.356ua\$

however: these numbers make sense if transistor not saturated. question states \$i_e \approx \beta * i_b\$ indicates in case not.